-- Feynman and Hibbs problem 6-13 Ea = p^2 / (2 m) lambda = 1 / hbar f = (m / (2 pi i hbar (tb - tc)))^(3/2) g = m Rbc^2 / (2 (tb - tc)) - Ea tc gp = d(g,tc) gpp = d(g,tc,tc) tc = tb - Rbc m / p "Verify tc" check(gp == 0) "ok" "Coefficient" simplify(-f sqrt(2 pi i / (lambda gpp))) "Exponential" simplify(exp(i lambda g))
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